Разложить на множители a) c+d+3x (c+d) б) 2a+ax+2bx+4b в) mn-3m+3-n г)2cx-3xy+6b...

kovaleva1999 @kovaleva1999

July 2021 2 33 Report

Разложить на множители a) c+d+3x (c+d) б) 2a+ax+2bx+4b в) mn-3m+3-n г)2cx-3xy+6by-4bc д)x^2-3ax+6a-2x е)a^2b - a -ab^2+b-2ab+2 ё)9,5*1,7-0,4*9,5+0,5*1,7-0,5*0,4

Artem112

Verified answer

a) c+d+3x(c+d)=(с+d)(1+3x)

б) 2a+ax+2bx+4b=a(2+x)+2b(x+2)=(x+2)(a+2b)

в) mn-3m+3-n=m(n-3)-(n-3)=(n-3)(m-1)

г)2cx-3xy+6by-4bc=2c(x-b)-3y(x-b)=(x-b)(2c-3y)

д)x^2-3ax+6a-2x=x(x-3a)-2(x-3a)=(x-3a)(a-2)

е)a^2b-a-ab^2+b-2ab+2=a(ab-1)-b(ab-1)+2(ab+1)=(ab+1)(a-b+2)

ё)9,5*1,7-0,4*9,5+0,5*1,7-0,5*0,4=1.7(9.5+0.5)-0.4(9.5+0.5)=(9.5+0.5)(1.7-0.4)=10*1.3=13

27 votes Thanks 26

rokfeller007

$(c+d)+3x(c+d)=(c+d)(1+3x)\\\\( 2a+ax)+(2bx+4b)=a(2+x)+2b(x+2)=(x+2)(a+2b)\\\\ (mn-3m)+(3-n)=m(n-3)-(n-3)=(n-3)(m-1)\\\\ (2cx-3xy)+(6by-4bc)=(2c(x-b))-(3y(x-b))=(x-b)(2c-3y)\\\\ (x^2-3ax)+(6a-2x)=x(x-3a)-2(x-3a)=(x-3a)(a-2)\\\\ (a^2b-a)-(ab^2-b)-(2ab-2)=a(ab-1)-b(ab-1)+2(ab+1)=(ab+1)(a-b+2)\\\\ 9,5*1,7-0,4*9,5+0,5*1,7-0,5*0,4=1.7(9.5+0.5)-0.4(9.5+0.5)=(9.5+0.5)(1.7-0.4)=10*1.3=13$

11 votes Thanks 8

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