разложить на множители (a+3b)^2-(3a-b)^2. Created by 2488at. algebra-ru

разложить на множители (a+3b)^2-(3a-b)^2...

kevrat

$(a+3b)^{2}-(3a-b)^{2}=a^{2}+6ab+9b^{2}-(9a^{2}-6ab+b^{2})= a^{2}+6ab+9b^{2}-9a^{2}+6ab-b^{2}=(6ab+6ab)+(a^{2}-9a^{2})+(9b^{2}-b^{2})=12ab-8a^{2}+8b^{2}$

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Svet1ana

Verified answer

a^2+6ab+9b^2-9a^2+6ab-b^2=12ab-8a^2+8b^2

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