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ledi903
@ledi903
September 2021
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Разложить на множители и решить по теореме виета:
1)х³-8х²+7х
2)х³-5х²+6х
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m11m
Verified answer
1) x³-8x²+7x=x(x²-8x+7)=x(x-1)(x-7)
x²-8x+7=0
x₁*x₂=7
x₁+x₂=8
x₁=1
x₂=7
2) x³-5x²+6x=x(x²-5x+6)=x(x-2)(x-3)
x²-5x+6=0
x₁*x₂=6
x₁+x₂=5
x₁=2
x₂=3
1 votes
Thanks 1
ledi903
надо решить по теореме виета по формуле х1,2
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Answers & Comments
Verified answer
1) x³-8x²+7x=x(x²-8x+7)=x(x-1)(x-7)x²-8x+7=0
x₁*x₂=7
x₁+x₂=8
x₁=1
x₂=7
2) x³-5x²+6x=x(x²-5x+6)=x(x-2)(x-3)
x²-5x+6=0
x₁*x₂=6
x₁+x₂=5
x₁=2
x₂=3