разложить на множители квадратный трехчлен 2x²+x-3
a)( 2x-3)(2x-2)
б)2(x-1)(x-1,5)
в)(x-1)(x-8)
г)(x+8)(x+1)
a)( 2x-3)(2x-2)
б)2(x-1)(x-1,5)
в)(x-1)(x-8)
г)(x+8)(x+1)
More Questions From This User See All
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2x² + x - 3 = 0
D = 1+ 24 = 25
x₁ = (-1+5)/4 = 1
x₂ = (-1-5)/4 = -3/2