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Mira1111
@Mira1111
July 2022
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разложить на множители квадратный трехчлен 2x²+x-3
a)( 2x-3)(2x-2)
б)2(x-1)(x-1,5)
в)(x-1)(x-8)
г)(x+8)(x+1)
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русская25
2x² + x - 3 = 2(x-1)(x+3/2)=(x-1)(2x+3)
2x² + x - 3 = 0
D = 1+ 24 = 25
x₁ = (-1+5)/4 = 1
x₂ = (-1-5)/4 = -3/2
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Thanks 1
Mira1111
тогда какая буква ответа?
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Answers & Comments
2x² + x - 3 = 0
D = 1+ 24 = 25
x₁ = (-1+5)/4 = 1
x₂ = (-1-5)/4 = -3/2