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ВладЛавров
@ВладЛавров
July 2022
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разложить на множители: x^(4)+4x^(2)-y^(2)+6y-5
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Checov7400
X^4+4x²-y²+6y-5=x^4+4x²-y²+6y-9+4=(x^4+4x²+4)-(y²-6y+9)=(x²+2)²-(y-3)²=
=((x²+2)-(y-3))((x²+2)+(y-3))=(x²+2-y+3)(x²+2+y-3)=(x²-y+5)(x²+y-1)
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Answers & Comments
=((x²+2)-(y-3))((x²+2)+(y-3))=(x²+2-y+3)(x²+2+y-3)=(x²-y+5)(x²+y-1)