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alenkabelovka
@alenkabelovka
August 2021
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Разложить на множители:
(y-4)(y+2)-(y-2)в квадрате
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m11m
(у-4)(у+2)-(у-2)²=
=у²-4у+2у-8-у²+4у-4=
=2у-12=
=2(у-6)
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Answers & Comments
=у²-4у+2у-8-у²+4у-4=
=2у-12=
=2(у-6)