Ответ:
Объяснение:
y³−y²−3y+27= y³+27-y²-3y=(y³+3³)-y(y+3)=
=(y+3)(y²-3y+9)-y(y+3) =(y+3)(y²-3y+9-y)= (y+3)(y²-4y+9)
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Ответ:
Объяснение:
y³−y²−3y+27= y³+27-y²-3y=(y³+3³)-y(y+3)=
=(y+3)(y²-3y+9)-y(y+3) =(y+3)(y²-3y+9-y)= (y+3)(y²-4y+9)