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butterfly19981
@butterfly19981
July 2022
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разложите многочлен 121-(t-8)^2 на линейные множители
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mzxcv1234
121-(t-8)^2=121-t^2+16t-64=-t^2+16t=57
t^2-16t-57=0
D=484
t1=19
t2=-3
t^2-16t-57=(t-t1)(t-t2)
(t-19)(t+3)=0
2 votes
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Answers & Comments
t^2-16t-57=0
D=484
t1=19
t2=-3
t^2-16t-57=(t-t1)(t-t2)
(t-19)(t+3)=0