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VadimGor
@VadimGor
July 2022
1
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Разложите многочлен на множетели
а) x²-7x+10
б) 7x²-63
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Juliaa21
A)
x²-7x+10=(x-5)(x-2)
x²-7x+10=0
D=49-4*1*10=49-40=9
x1=(7+3)/2=10/2=5
x2=(7-3)/2=4/2=2
б)
7x²-63=7(x-3)(x+3)
7x²-63=0
7x²=63
x²=63/7
x²=9
x=+-3
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Answers & Comments
x²-7x+10=(x-5)(x-2)
x²-7x+10=0
D=49-4*1*10=49-40=9
x1=(7+3)/2=10/2=5
x2=(7-3)/2=4/2=2
б)
7x²-63=7(x-3)(x+3)
7x²-63=0
7x²=63
x²=63/7
x²=9
x=+-3