2b³-6-4b²+3b= (2b³-4b²)+(3b-6)= 2b²(b-2)+3(b-2)=(b-2)(2b²+3).
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2b³-6-4b²+3b= (2b³-4b²)+(3b-6)= 2b²(b-2)+3(b-2)=(b-2)(2b²+3).