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markkulesh
@markkulesh
July 2022
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Разложите многочлен на множители а) х(у + k) + 5у + 5k; б) 4а + 4b + са + cb
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FickenLuder
A) x(y+k)+5y+5k=x(y+k)+5(y+k)=(y+k)(x+5)
b) 4a+4b+ca+cb=(4a+4b)+(ca+cb)=4(a+b)+c(a+b)=(a+b)(4+c)
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Answers & Comments
b) 4a+4b+ca+cb=(4a+4b)+(ca+cb)=4(a+b)+c(a+b)=(a+b)(4+c)