разложите множители на многочлен 2n(во второй степени)-3an-10n+15n
(5+n)(2n-3n)
(2n−5)(n+3a)
(3a−n)(5−2n)
(2n+3a)(n+5)
(5−n)(3a−2n)
(5+n)(2n-3n)
(2n−5)(n+3a)
(3a−n)(5−2n)
(2n+3a)(n+5)
(5−n)(3a−2n)
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Verified answer
2n^2-3an-10n+15n=2n^2-3an+5n(5+n)(2n-3n)=10n-15n+2n^2-3n^2=-5n-n^2=-(5n+n^2)
(2n−5)(n+3a)=2n^2+6an-5n-15a
(3a−n)(5−2n)=15a-6an-5n+10n^2
(2n+3a)(n+5)=2n^2+10n+3an+15a
(5−n)(3a−2n)=15a-10n-3an+6n^2