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msalimat
@msalimat
August 2022
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Разложите на множетели 2 пример
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irreversibility
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(а+3b)²-(3a-b)²=(a+3b-(3a-b))(a+3b+3a-b)=(a+b-3a+b)(4a+2b)=(-2a+4b)2(2a+b)=(-2(a-2b))2(2a+b)=-4(a-2b)(2a+b).
2 votes
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msalimat
А если 18ab^3-2a^3b
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Verified answer
(а+3b)²-(3a-b)²=(a+3b-(3a-b))(a+3b+3a-b)=(a+b-3a+b)(4a+2b)=(-2a+4b)2(2a+b)=(-2(a-2b))2(2a+b)=-4(a-2b)(2a+b).