1). 1 - 125с³ = 1³ - (5с)³ = (1 - 5с)(1 + 5с + 25с²);
2). -64q¹² + 27q⁹ = q⁹(27 - 64q³) = q⁹(3³ - (4q)³) =
= q⁹(3 - 4q)(9 + 12q + 16q²);
3). t³ + 27 = t³ + 3³ = (t + 3)(t² - 3t + 9);
4). (x - 1)³ + 8 = (x - 1)³ + 2³ = (x - 1 + 2)((x - 1)² - 2(x - 1) + 4) =
= (x + 1)(x² - 2x + 1 - 2x + 2 + 4) = (x + 1)(x² - 4x + 7);
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1). 1 - 125с³ = 1³ - (5с)³ = (1 - 5с)(1 + 5с + 25с²);
2). -64q¹² + 27q⁹ = q⁹(27 - 64q³) = q⁹(3³ - (4q)³) =
= q⁹(3 - 4q)(9 + 12q + 16q²);
3). t³ + 27 = t³ + 3³ = (t + 3)(t² - 3t + 9);
4). (x - 1)³ + 8 = (x - 1)³ + 2³ = (x - 1 + 2)((x - 1)² - 2(x - 1) + 4) =
= (x + 1)(x² - 2x + 1 - 2x + 2 + 4) = (x + 1)(x² - 4x + 7);