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Cybran21312
@Cybran21312
April 2022
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Разложите на множители 1) 2с(1+с)-(с-2)(с+4)
2) (y+2)^2-2y(y+2)
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manglx
1) 2с+2с(в квадрате) -с(в квадрате) +4c-2c-8
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natylia64
1) 2c(1+c)-(c-2)(c+4)=2c+2c^2-(c^2+4c-2c-8)=2c+2c^2-c^2-4c+2c+8=
c^2+8
2) (y+2)^2-2y(y+2)=y^2+4y+4-2y^2-4y=4-y^2
1 votes
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Answers & Comments
c^2+8
2) (y+2)^2-2y(y+2)=y^2+4y+4-2y^2-4y=4-y^2