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sashalpatova
@sashalpatova
August 2022
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Разложите на множители 10x-10y+ax-at
Упрости выражение ( 3y-2)(5-6y)+18y(во 2 степени)
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selmash21
10х-10у+ах-ау=10(х-у)+а(х-у)=(х-у)(10+а)
(3у-2)(5-6у)+18у^2=15у-18у^2-10+12у+18у^2=
=27у-10
1 votes
Thanks 3
sashalpatova
можешь еще решить?
sashalpatova
разложите на множители трехчлен
sashalpatova
a^2+6a+8
selmash21
=а^2+2а+4а+8=а(а+2)+4(а+2)=(а+2)(а+4)
kdid
10x-10y+ax-at=10(x-y)+a(x-t)
( 3y-2)(5-6y)+18y
²=15y-18y²-10+12y+18y²=27y-10
0 votes
Thanks 0
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Answers & Comments
(3у-2)(5-6у)+18у^2=15у-18у^2-10+12у+18у^2=
=27у-10