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TheDarMaK
@TheDarMaK
July 2022
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Разложите на множители
32a^4b-162b
Решите уравнения
(x^2-7x)-x+7=0
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ВикаВикторовна
Verified answer
1. 32a⁴b-162b = 2b(16a⁴-81) = 2b((4a²)²-9²) = 2b(4a²-3)(4a²+3)
2. (х²-7х)-х+7 = 0
х(х-7)-(х-7) = 0
х(х-7)(х-1) = 0
х₁ = 0
х-7=0
х₂ = 7
х-1=0
х₃ = 1
х = 0; 1; 7
3. 2 2/3 / х + 1/3 = 1 1/2 / х - 1 1/8
2 2/3(х - 1 1/8) = 1 1/2(х + 1/3)
8/3(х - 9/8) = 3/2(х + 1/3)
8/3 х - 8/3*9/8 = 3/2 х + 3/2*1/3
8/3 х - 3 = 3/2 х + 1/2
8/3 х - 3/2 х = 1/2 + 3
16/6 х - 9/6 х = 3 1/2
7/6 х = 7/2
х = 7/2 : 7/6
х = 7/2 * 6/7
х = 3
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Answers & Comments
Verified answer
1. 32a⁴b-162b = 2b(16a⁴-81) = 2b((4a²)²-9²) = 2b(4a²-3)(4a²+3)2. (х²-7х)-х+7 = 0
х(х-7)-(х-7) = 0
х(х-7)(х-1) = 0
х₁ = 0
х-7=0
х₂ = 7
х-1=0
х₃ = 1
х = 0; 1; 7
3. 2 2/3 / х + 1/3 = 1 1/2 / х - 1 1/8
2 2/3(х - 1 1/8) = 1 1/2(х + 1/3)
8/3(х - 9/8) = 3/2(х + 1/3)
8/3 х - 8/3*9/8 = 3/2 х + 3/2*1/3
8/3 х - 3 = 3/2 х + 1/2
8/3 х - 3/2 х = 1/2 + 3
16/6 х - 9/6 х = 3 1/2
7/6 х = 7/2
х = 7/2 : 7/6
х = 7/2 * 6/7
х = 3