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alisaparov2013
@alisaparov2013
July 2022
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Разложите на множители (3—5):
3. ху + Зу + xz + 3z. 4. 25 - с². 5. ab² - 2аbс + ас²
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amina254
Verified answer
3. ху + Зу + xz + 3z=х(у+z)+3(y+z)=(y+z)(x+3)
4. 25 - с²=(5-c)(5+c).
5. ab² - 2аbс + ас²=a(b²-2bc+c²)=a(b-c)²
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Answers & Comments
Verified answer
3. ху + Зу + xz + 3z=х(у+z)+3(y+z)=(y+z)(x+3)4. 25 - с²=(5-c)(5+c).
5. ab² - 2аbс + ас²=a(b²-2bc+c²)=a(b-c)²