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наталья32095317
@наталья32095317
August 2022
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разложите на множители 3х^2+12ху+12у^2=
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markiza7100
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1) 3х^2+12ху+12у^2 = 3(х^2+4ху+4у^2)= 3(х+2у) ^2
2) 8a(b-3)+c(3-b)= 8a(b-3)-c(b-3)= (b-3)(8а-с)
3)х^2+3х-2ху-6у= (х^2+3х) +(-2ху-6у) = х (х+3)-2у (х+3)= (х+3)(х-2у)
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Answers & Comments
1) 3х^2+12ху+12у^2 = 3(х^2+4ху+4у^2)= 3(х+2у) ^2
2) 8a(b-3)+c(3-b)= 8a(b-3)-c(b-3)= (b-3)(8а-с)
3)х^2+3х-2ху-6у= (х^2+3х) +(-2ху-6у) = х (х+3)-2у (х+3)= (х+3)(х-2у)