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YchenickIzShkoly
@YchenickIzShkoly
July 2022
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разложите на множители
(3+q)^3+(3+5q)^3
(p-1)^3+(4+4p)^3
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nKrynka
(3+q)^3+(3+5q)^3 = (3 + q + 3 + 5q)*[(3 + q)² - (3 + q)*(3 + 5q) + (3 + 5q)²] =
= 6*(1 + q)*(9 + 6q + q² - 9 - 18q - 5q² + 9 + 30q + 25q²) =
= 18*(1 + q)*(7q² + 6q + 3)
(p-1)^3+(4+4p)^3 = (p - 1 + 4 + 4p)*[(p - 1)
² - (p -1)*(4 + 4p) + (4 + 4p)²] =
= (5p + 3)*(p² - 2p + 1 - 4p² + 4 + 16 + 32p + 16p²) =
= (5p + 3)*(13p² + 30p + 21)
3 votes
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YchenickIzShkoly
СПАСИБО ОГРОМНОЕ!!!
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Answers & Comments
= 6*(1 + q)*(9 + 6q + q² - 9 - 18q - 5q² + 9 + 30q + 25q²) =
= 18*(1 + q)*(7q² + 6q + 3)
(p-1)^3+(4+4p)^3 = (p - 1 + 4 + 4p)*[(p - 1)² - (p -1)*(4 + 4p) + (4 + 4p)²] =
= (5p + 3)*(p² - 2p + 1 - 4p² + 4 + 16 + 32p + 16p²) =
= (5p + 3)*(13p² + 30p + 21)