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Kimlifga
@Kimlifga
September 2021
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разложите на множители (3x-1)(8b+1)+(7b-3)(1-3x)
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ignatcompass
(3x-1)(8b+1)+(7b-3)(1-3x)=(3х-1)[(8b+1)-(7b-3)]==(3x-1)(8b+1-7b+3)=(3x-1)(b+4)
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