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TOFeFE
@TOFeFE
August 2022
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Разложите на множители
49c^2-14c+1-21ac+3a
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подкожного
49с^2-14с+1-21ас+3а=(7с-1)^2-3а (7с-1)=(7с-1)(7с-1-3а)
6 votes
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подкожного
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