Разложите на множители: 5x²-5 2a²-8 3an²-27a 2xy²-50x x³9x 3y³-3y 2a³-8a 40b-10b³. Created by ksusha5165. algebra-ru

5-5=5(-1)=5*(х-1)(х+1)2-8=2(-4)=2(а-2)(а+2)3а-27a=3a(-9)=3f(n-3)(n+3)2x-50x=2x(-25)=2x(y-5)(y+5)-9x=x(-9)=x(x-3)(x+3)3-3y=3y(-1)=3y(y-1)(y+1)2-8a=2a(-4)=2a(a-2)(a+2)40b-10=10b(4-)=10b(2-b)(2+b)

Разложите на множители: 5x²-5 2a²-8 3an²-27a 2xy²-50x x³9x 3y³-3y 2a³-8a 40b-10b...

ksusha5165 @ksusha5165

August 2022 1 4 Report

Разложите на множители:
5x²-5
2a²-8
3an²-27a
2xy²-50x
x³9x
3y³-3y
2a³-8a
40b-10b³

Answers & Comments

Lunok 5 $x^{2}$ -5=5( $x^{2}$ -1)=5*(х-1)(х+1)
2 $а^{2}$ -8=2( $а^{2}$ -4)=2(а-2)(а+2)
3а $n^{2}$ -27a=3a( $n^{2}$ -9)=3f(n-3)(n+3)
2x $y^{2}$ -50x=2x( $y^{2}$ -25)=2x(y-5)(y+5)
$x^{3}$ -9x=x( $x^{2}$ -9)=x(x-3)(x+3)
3 $y^{3}$ -3y=3y( $y^{2}$ -1)=3y(y-1)(y+1)
2 $a^{3}$ -8a=2a( $a^{2}$ -4)=2a(a-2)(a+2)
40b-10 $b^{3}$ =10b(4- $b^{2}$ )=10b(2-b)(2+b)

Answers & Comments

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