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PonyMaKc
@PonyMaKc
July 2022
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Разложите на множители:
a) 100a²-20a²+1
б)81x²-25y²
в)27x³-125y³
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233334
А) 100a²-20a+1=(10a-1)²
б) 81x²-25y²=(9x-5y)*(9x+5y)
в) 27x³-125y³=(3x-5y)*(9x²+15xy+25y²)
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Answers & Comments
б) 81x²-25y²=(9x-5y)*(9x+5y)
в) 27x³-125y³=(3x-5y)*(9x²+15xy+25y²)