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Черносливка96
@Черносливка96
July 2022
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Разложите на множители: а) 32q^4 - 2q^2
б) a^3-2a^2-4a+8
в) 3n^2+2n-5
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deadpun
А) 32q^4-2q^2= 2q^2(18q^2-1)
б) a^3-2a^2-4a+8 =
(a^3-2a^2)-(4a-8)= a^2(a-2) -4(a-2) = (a^2-4)(a-2)
в) 3n^2+2n-5 = (3n^2+2n) -5 = 2n(n +1) -5
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Черносливка96
27d^2-16c^2- реши, пожалуйста)
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Answers & Comments
б) a^3-2a^2-4a+8 = (a^3-2a^2)-(4a-8)= a^2(a-2) -4(a-2) = (a^2-4)(a-2)
в) 3n^2+2n-5 = (3n^2+2n) -5 = 2n(n +1) -5