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anchoucs
@anchoucs
August 2022
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Разложите на множители:
а) a^3-a^2-3a+3
б) 4b^2-(b+8)^2
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Answers & Comments
klepa300
А) a^2(a-1)-3(a-1)=(a-1)(a^2-3)
б) не могу догадаться
1 votes
Thanks 1
anchoucs
Спасибо
прр40
4b²-(b+8)²=4b²-(b²+16b+64)=4b²-b²-16b-64=
=3b²-16b-64
3b²-16b-64=0
D=256-4*3*(-64)=256+768=1024
b= 16+32/2*3=48/6=8
b=16-32/6= -16/6= -8/3
3b²-16b-64=3(b+8/3)(b-8)=(3b+8)(b-8)
наверно так
1 votes
Thanks 0
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Answers & Comments
б) не могу догадаться
=3b²-16b-64
3b²-16b-64=0
D=256-4*3*(-64)=256+768=1024
b= 16+32/2*3=48/6=8
b=16-32/6= -16/6= -8/3
3b²-16b-64=3(b+8/3)(b-8)=(3b+8)(b-8)
наверно так