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dinara23062002
@dinara23062002
April 2021
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Разложите на множители: (а+1)в кубе) --8а в шестой степени
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krugly1981
( a + 1)^3 - 8a^6 = ( a + 1)^3 - (2a^2)^3 = ( a + 1 - 2a^2)(a^2+2a+1+2a^3+
+ 2a^2 + 4a^4) = ( - 2a^2 + a + 1)(4a^4 + 2a^3 + 3a^2 + 2a + 1)
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Answers & Comments
+ 2a^2 + 4a^4) = ( - 2a^2 + a + 1)(4a^4 + 2a^3 + 3a^2 + 2a + 1)