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Dias0501241
@Dias0501241
November 2021
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Разложите на множители a^3 + ab^2 - a^2b-b^3 ( a в третьей степени + a* b в квадрате - a в квадрате * b - b в третьей)
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Montale
А³+ab²-a²b-b³=-b³+ab²-a²b+a³=(a-b)*(b²+a²)
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