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yfiyt
@yfiyt
July 2022
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Разложите на множители (а+4) ^3-27;
(а-9)^3+64
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nafanya2014
Verified answer
(а+4) ³-27=(a+4)³-3³=(a+4-3)·((a+4)²+3(a+4)+9)=(a+1)(a²+11a+25);
(а-9)³+64=(a-9)³+4³=(a-9+4)·((a-9)²-4(a-9)+4²)=(a-5)(a²-22a+133)
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Verified answer
(а+4) ³-27=(a+4)³-3³=(a+4-3)·((a+4)²+3(a+4)+9)=(a+1)(a²+11a+25);(а-9)³+64=(a-9)³+4³=(a-9+4)·((a-9)²-4(a-9)+4²)=(a-5)(a²-22a+133)