Home
О нас
Products
Services
Регистрация
Войти
Поиск
nastya1000000
@nastya1000000
July 2022
2
2
Report
РАЗЛОЖИТЕ НА МНОЖИТЕЛИ а)ab+ac-b-c б)mn-m+n-1 в)bd-ad+3a-3b г)2b-2c+ab-ac
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Monika55
1) ab+ac-b-c
(a-1)*(c+b)
2) mn-m+n-1
(m+1)*(n-1)
3)
bd-ad+3a-3b
(b-a)*(d-3)
4)
2b-2c+ab-ac
(-(a+2))*(c-b)
2 votes
Thanks 1
LoneWolf152
A) a(b+c)-(b+c)=(a-1)(b+c)
b)m(n-1)+(n-1)=(m+1)(n-1)
в)d(b-a)-3(b-a)=(d-3)(b-a)
г)2(b-c)+a(b-c)=(2+a)(b-c)
2 votes
Thanks 4
More Questions From This User
See All
nastya1000000
August 2021 | 0 Ответы
u 3 u3 vypolnite umnozheniya
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "РАЗЛОЖИТЕ НА МНОЖИТЕЛИ а)ab+ac-b-c б)mn-m+n-1 в)bd-ad+3a-3b ..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(a-1)*(c+b)
2) mn-m+n-1
(m+1)*(n-1)
3) bd-ad+3a-3b
(b-a)*(d-3)
4) 2b-2c+ab-ac
(-(a+2))*(c-b)
b)m(n-1)+(n-1)=(m+1)(n-1)
в)d(b-a)-3(b-a)=(d-3)(b-a)
г)2(b-c)+a(b-c)=(2+a)(b-c)