a(b - c) - (c - b)=a(b - c) + ( b-c)=(a+1)(b-c)
Ответ:
a(b-c)-(c-b)=a×(b-c)-(-(b-c))=a×(b-c)+(b-c)=(b-c)×(a+1)
(a-1)(b-c)=ab-ac-b-1×(-c)=ab-ac-b+1c=ab-ac-b+c
(a+1)(b-c)=ab-ac+b-c
(a-1)(c-b)=ac-ab-c-1×(-b)=ac-ab-c+1b=ac-ab-c+b
(a+1)(c-b)=ac-ab+c-b
Если неправильно, то извините
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a(b - c) - (c - b)=a(b - c) + ( b-c)=(a+1)(b-c)
Ответ:
a(b-c)-(c-b)=a×(b-c)-(-(b-c))=a×(b-c)+(b-c)=(b-c)×(a+1)
(a-1)(b-c)=ab-ac-b-1×(-c)=ab-ac-b+1c=ab-ac-b+c
(a+1)(b-c)=ab-ac+b-c
(a-1)(c-b)=ac-ab-c-1×(-b)=ac-ab-c+1b=ac-ab-c+b
(a+1)(c-b)=ac-ab+c-b
Если неправильно, то извините