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ZORRO1066
@ZORRO1066
September 2021
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разложите на множители: г,е,ж. Заранее спасибо!
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zxcvbnm123321
А) а^3*b^3*(b-1)-a*b^5*(b-1)=(a^3*b^3-a*b^5)(b-1)
e)b*a^3*(a+1)-b^7*a^3*(a+1)=(b*a^3-b^7*a^3)(a+1)
ж)x^2*y^2(x+1)+x*y(x+1)-2(x+1)=(x^2*y^2+x*y-2)(x+1)
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Answers & Comments
e)b*a^3*(a+1)-b^7*a^3*(a+1)=(b*a^3-b^7*a^3)(a+1)
ж)x^2*y^2(x+1)+x*y(x+1)-2(x+1)=(x^2*y^2+x*y-2)(x+1)