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ZozulyaZina
@ZozulyaZina
July 2022
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Разложите на множители квадратный трехчлен: 1 12x^2+5x-2 -21x^2+x+2
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Fandered751953
12x^2+5x-2D=25+96=121x1=-2/3x2=0.25...=12(x+2/3)(x-0.25)=(3x+2)(4x-1)
-21x^2+x+2D=1+168=169x1=1/3x2=-2/7...=-21(x-1/3)(x+2/7)=(-3x+1)(7x+2),
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Answers & Comments
-21x^2+x+2D=1+168=169x1=1/3x2=-2/7...=-21(x-1/3)(x+2/7)=(-3x+1)(7x+2),