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@помогите413
August 2022
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Разложите на множители квадратный трехчлен: -16x^2+8x+3
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rjkz2792009
-16x
²+8x+3 = 0
D1 = 4
²+16*3 = 16+48 = 64
x1 = (-4-8)/(-16) = 3/4
x2 = (-4+8)/(-16) = -1/4
-16x²+8x+3 = -16(x+1/4)(x-3/4) = -(4x+1)(4x-3) = (4x+1)(3-4x)
Ответ: (4x+1)(3-4x).
0 votes
Thanks 1
hraky
-16х^2+8х+3=-(16х^2-8х+1-4)=-((4х-1)^2-4)=-((4х-1-2)(4х-1+2))=-((4х-3)(4х+1))=-(4х-3)(4х+1)
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Answers & Comments
D1 = 4²+16*3 = 16+48 = 64
x1 = (-4-8)/(-16) = 3/4
x2 = (-4+8)/(-16) = -1/4
-16x²+8x+3 = -16(x+1/4)(x-3/4) = -(4x+1)(4x-3) = (4x+1)(3-4x)
Ответ: (4x+1)(3-4x).