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tate4
@tate4
September 2021
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разложите на множители квадратный трёхчлен
х2-12х+20
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ЛюблюСвойКласс
Verified answer
Ax^2+bx+c=a(x-x1)(x-x2)
x^2-12x+20=0
D=144-80=64
x1=(12+8)/2=10 х2=(12-8)/2=2
x^2-12+20=(x-10)(x-2)
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Answers & Comments
Verified answer
Ax^2+bx+c=a(x-x1)(x-x2)x^2-12x+20=0
D=144-80=64
x1=(12+8)/2=10 х2=(12-8)/2=2
x^2-12+20=(x-10)(x-2)