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stas14220
@stas14220
July 2022
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Разложите на множители левую часть уравнения и найдите его корень:
x^{3} - 5 x^{2} + x - 5 = 0
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ewgenijbark
Verified answer
Х³-5х²+х-5 = 0
х²(х - 5) + (х - 5) = 0
(х - 5)(х² + 1) = 0
х - 5 = 0 х² + 1 = 0
х = 5 х² = - 1
решения нет
Ответ. х=5
1 votes
Thanks 3
flsh
Verified answer
X³ - 5x² + x - 5 = 0
x²(x - 5) + x - 5 = 0
(x - 5) (x² + 1) = 0
x² + 1 > 0 при любых х,
поэтому: х - 5 = 0
х = 5
1 votes
Thanks 1
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Answers & Comments
Verified answer
Х³-5х²+х-5 = 0х²(х - 5) + (х - 5) = 0
(х - 5)(х² + 1) = 0
х - 5 = 0 х² + 1 = 0
х = 5 х² = - 1
решения нет
Ответ. х=5
Verified answer
X³ - 5x² + x - 5 = 0x²(x - 5) + x - 5 = 0
(x - 5) (x² + 1) = 0
x² + 1 > 0 при любых х,
поэтому: х - 5 = 0
х = 5