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AnnaMarkeca91
@AnnaMarkeca91
July 2022
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Разложите на множители
mn-2m+4n-8
x^2+3xy-4y^2
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tersoleg1972
Mn-2m+4n-8=m(n-2)+4(n-2)=(m+4)(n-2)
x^2+3xy-4y^2=
x^2-xy+4xy-4y^2=x(x-y)+4y(x-y)=(x-y)(x+4y)
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Answers & Comments
x^2+3xy-4y^2=x^2-xy+4xy-4y^2=x(x-y)+4y(x-y)=(x-y)(x+4y)