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diana9593
@diana9593
September 2021
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Разложите на множители многочлен 16a2 – 81
1) (4x – 9)2 2) 16(x2 – 81) 3) (16x – 9)(16x + 9) 4) (4x – 9)(4x + 9)
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BOG21281
Ответ:
Будет 4) (4x-9) (4x+9)
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Ответ:
Будет 4) (4x-9) (4x+9)