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AnastasiyaLiL
@AnastasiyaLiL
July 2022
1
7
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Разложите на множители :
( ^ -степень )
а)
3ab+ a^2
б)
4b^3 - 3b^5
в)
-15a^3b - 5ab^2 - 10a^2b^4
г)
5y(x+y) + x(x+y)
д)
2a-ax+2b-bx
е)
20m^2 - 5n^4
ж)
-5x^2 +20x-20
з)
64a^3 -b^3
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Answers & Comments
Bergo
А)
3ab+ a^2 = a(3b+a)
б)
4b^3 - 3b^5 = b^3(4-3b^2)
в)
-15a^3b - 5ab^2 - 10a^2b^4 = -5ab(3a^2-b-2ab^3)
г)
5y(x+y) + x(x+y) = 5yx+5y^2+x^2+xy=6xy+6x^2=6x(y+x)
д)
2a-ax+2b-bx = (2a+2b)(-ax-bx)
е)
20m^2 - 5n^4 = 5(4m^2-n^2)=5(2m-n)(2m+n)
ж)
-5x^2 +20x-20 = -5(x^2-4x+4)=-5(x-2)^2
з)
64a^3 -b^3 = (4a-b)(16a^2+4ab+b^2)
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Answers & Comments
б) 4b^3 - 3b^5 = b^3(4-3b^2)
в) -15a^3b - 5ab^2 - 10a^2b^4 = -5ab(3a^2-b-2ab^3)
г) 5y(x+y) + x(x+y) = 5yx+5y^2+x^2+xy=6xy+6x^2=6x(y+x)
д) 2a-ax+2b-bx = (2a+2b)(-ax-bx)
е) 20m^2 - 5n^4 = 5(4m^2-n^2)=5(2m-n)(2m+n)
ж) -5x^2 +20x-20 = -5(x^2-4x+4)=-5(x-2)^2
з) 64a^3 -b^3 = (4a-b)(16a^2+4ab+b^2)