разложите на множители второе и третие задание)
2. а) (p-q)*(8p+q)
б) x(b-c)+6(b-c)=(b-c)*(x+b)
3. (2c-8d) в кавдрате
2.
a) 8p(p-q)+q(p-q)=(p-q)(8p+q)
б) bx+6b-xc-6c = x(b-c)+6(b-c)=(b-c)(x+6)
3.
a) 4c²-64d⁴ = 4(c²-16d⁴)=4(c-4d²)(c+4d²)
б) -18a²+12a-2=-2(9a²-6a+1) = -2(3a-1)²
в) 1/27a³+b³ = (1/3)³a³+b³ = (1/3a+b)(1/9a²-1/3ab+b²)
4.
x³-4x²-16x+64=(x³-16x)-(4x²-64)=x(x²-16)-4(x²-16)=(x²-16)(x-4) = (x-4)(x+4)(x-4) = (x-4)²(x+4)
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Answers & Comments
2. а) (p-q)*(8p+q)
б) x(b-c)+6(b-c)=(b-c)*(x+b)
3. (2c-8d) в кавдрате
2.
a) 8p(p-q)+q(p-q)=(p-q)(8p+q)
б) bx+6b-xc-6c = x(b-c)+6(b-c)=(b-c)(x+6)
3.
a) 4c²-64d⁴ = 4(c²-16d⁴)=4(c-4d²)(c+4d²)
б) -18a²+12a-2=-2(9a²-6a+1) = -2(3a-1)²
в) 1/27a³+b³ = (1/3)³a³+b³ = (1/3a+b)(1/9a²-1/3ab+b²)
4.
x³-4x²-16x+64=(x³-16x)-(4x²-64)=x(x²-16)-4(x²-16)=(x²-16)(x-4) = (x-4)(x+4)(x-4) = (x-4)²(x+4)