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HarukaHaruna
@HarukaHaruna
July 2022
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разложите на множители xy3-by3-ax+ab-a+y3
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olyaozered
3ху-3by-ax+ab-a+3y=(3xy+3y)+(ab-3by)-(ax+a)=3y(x+1)+b(a-3y)-a(x+1)=
=(3y(x+1)-a(x+1))+b(a-3y)=(x+1)(3y-a)+b(a-3y)=(x+1)(3y-a)-b(3y-a)=
=(3y-a)(x+1-b);
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=(3y(x+1)-a(x+1))+b(a-3y)=(x+1)(3y-a)+b(a-3y)=(x+1)(3y-a)-b(3y-a)=
=(3y-a)(x+1-b);