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Westix
@Westix
March 2022
2
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Разложите на множители:
1000−10y−y2+y3
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Jeltaia
(10+у)(100-10у+у^2)-у(10+у)=(10+у)(100-11у+у^2)
2 votes
Thanks 0
konstantsya
1000−10y−y²+y³ = 10³+y³ −10y−y² = (10+у)(10²-10у+у²)-у(10+у) =
= (10+у)((10²-10у+у²)-у) = (10+у)(100-10у+у²-у) = (10+у)(у²-11у+100)
4 votes
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Answers & Comments
= (10+у)((10²-10у+у²)-у) = (10+у)(100-10у+у²-у) = (10+у)(у²-11у+100)