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тупик123457
@тупик123457
August 2022
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разложите на множители:
2а^2-2в^2-а+в =
х-у-3х^2+3у^2 =
2х+у+у^2-4х^2 =
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sedinalana
2а^2-2в^2-а+в =2(a-b)(a+b)-(a-b)=(a-b)(2a+2b-1)
х-у-3х^2+3у^2 =(x-y)-3(x-y)(x+y)=(x-y)(1-3x-3y)
2х+у+у^2-4х^2 =(2x+y)-(2x-y)(2x+y)=(2x+y)(1-2x+y)
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Answers & Comments
х-у-3х^2+3у^2 =(x-y)-3(x-y)(x+y)=(x-y)(1-3x-3y)
2х+у+у^2-4х^2 =(2x+y)-(2x-y)(2x+y)=(2x+y)(1-2x+y)