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abnurtazina
@abnurtazina
July 2022
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Разложите на множители(2x+3y)^3+(3x-2y)^3
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Ртуть3
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Сумма кубов:
(2x+3y)^3+(3x-2y)^3=(2x+3y+3x-2y)((2x+3y)^2-(2x+3y)(3x-2y)+(3x-2y)^2)=(5x+y)(4x^2+12xy+9y^2-6x^2-9xy+4xy+6y^2+9x^2-12xy+4y^2)=(5x+y)(7x^2+19y^2-5xy)
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Verified answer
Сумма кубов:(2x+3y)^3+(3x-2y)^3=(2x+3y+3x-2y)((2x+3y)^2-(2x+3y)(3x-2y)+(3x-2y)^2)=(5x+y)(4x^2+12xy+9y^2-6x^2-9xy+4xy+6y^2+9x^2-12xy+4y^2)=(5x+y)(7x^2+19y^2-5xy)