Home
О нас
Products
Services
Регистрация
Войти
Поиск
abnurtazina
@abnurtazina
July 2022
1
10
Report
Разложите на множители(2x+3y)^3+(3x-2y)^3
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Ртуть3
Verified answer
Сумма кубов:
(2x+3y)^3+(3x-2y)^3=(2x+3y+3x-2y)((2x+3y)^2-(2x+3y)(3x-2y)+(3x-2y)^2)=(5x+y)(4x^2+12xy+9y^2-6x^2-9xy+4xy+6y^2+9x^2-12xy+4y^2)=(5x+y)(7x^2+19y^2-5xy)
29 votes
Thanks 55
More Questions From This User
See All
abnurtazina
July 2022 | 0 Ответы
u dvuh malchikov 15 yablokesli pervyj dast vtoromu 4 yabloka to u nego yablok bud
Answer
abnurtazina
July 2022 | 0 Ответы
napisat imena sushestvitelnye obshego roda gruppami 1sostoyanie cheloveka 2chert
Answer
abnurtazina
December 2021 | 0 Ответы
reshit 5 7h 12 h13 3 7u 1 u1 2u5 12
Answer
abnurtazina
November 2021 | 0 Ответы
eldos zadumal chetyre chisla sootnoshenie kotoryh ravno 2358 summa pervogo i t
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Разложите на множители(2x+3y)^3+(3x-2y)^3..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Сумма кубов:(2x+3y)^3+(3x-2y)^3=(2x+3y+3x-2y)((2x+3y)^2-(2x+3y)(3x-2y)+(3x-2y)^2)=(5x+y)(4x^2+12xy+9y^2-6x^2-9xy+4xy+6y^2+9x^2-12xy+4y^2)=(5x+y)(7x^2+19y^2-5xy)