Verified answer

16x^2-24xy+9y^2-4x+3y

(4x)^2-2*3*4xy+(3y)^2-4x+3y

(3y-4x)^2-4x+3y

(3y-4x)^2+3y-4x

(3y-4x)(3y-4x)+3y-4x

(3y-4x)(3y-4x+1) 

   Вот так   !

16х^2-24ху+9у^2-4х+3у= (16х^2-24ху+9у^2) - (4х-3у)= (4х-3у)^2 - (4х-3у)=(4х-3у)(4х-3у-1)