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Vika962
@Vika962
July 2022
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Разложите на множители:
81(9х^2+7)^2 - 16(4x^2-3)^2
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massg
Разность квадратов надо увидеть
(9(9x^2+7)+4(4x^2-3))*(9(9x^2+7)-4(4x^2-3))=
=(81x^2+63+16x^2-12)*(81x^2+63-16x^2+12)=
=(97x^2+51)*(65x^2+75)=
=5*(97x^2+51)*(13x^2+15) и всё :-)
1 votes
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Answers & Comments
(9(9x^2+7)+4(4x^2-3))*(9(9x^2+7)-4(4x^2-3))=
=(81x^2+63+16x^2-12)*(81x^2+63-16x^2+12)=
=(97x^2+51)*(65x^2+75)=
=5*(97x^2+51)*(13x^2+15) и всё :-)