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rkalashnikov
@rkalashnikov
August 2022
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разложите на множители
(х-2у)^2-(2x+у)
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mmb1
Verified answer
(х-2у)^2-(2x+у)=x²-4xy+4y²-2x-y
=========================
(х-2у)^2-(2x+у)^2=(x-2y-2x-y)(x-2y+2x+y)=(-x-3y)(3x-y)
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rkalashnikov
(x-2y-2x-y)(x-2y+2x+y)=(-x-3y)(3x-y) это как получается?
rkalashnikov
(х-2у)^2-(2x+у)^2=(x-2y-2x-y)(x-2y+2x+y) это формула
Andron1k
Если твой пример вот такой как ты сказал
(х-2у)^2-(2x+у)^2 ... то ответ будет
(y-3x)*(3y+x)
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Answers & Comments
Verified answer
(х-2у)^2-(2x+у)=x²-4xy+4y²-2x-y=========================
(х-2у)^2-(2x+у)^2=(x-2y-2x-y)(x-2y+2x+y)=(-x-3y)(3x-y)
(y-3x)*(3y+x)