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Romanovna1593
@Romanovna1593
September 2021
2
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Разложите нв множетели трёхчлен x^2+15x+50
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1Snezhka1
x^2+15x+50 = 0
D = b^2 - 4ac = 225 - 200 = 25 = 5^2
x1 = (-15 + 5) / 2 = -5
x2 = (-15 - 5) / 2 = - 10
х^2+15x+50 = (x - x1)(x-x2) = (x + 5)(x + 10)
5 votes
Thanks 1
Andersonepta
D=225-4×1×50=25
x1=-15+5/2=-5
x2=-15-5/2=-10
a(x-x1)(x-x2)
(x+5)(x+10) Это и есть x^2+15x+50
3 votes
Thanks 1
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Answers & Comments
D = b^2 - 4ac = 225 - 200 = 25 = 5^2
x1 = (-15 + 5) / 2 = -5
x2 = (-15 - 5) / 2 = - 10
х^2+15x+50 = (x - x1)(x-x2) = (x + 5)(x + 10)
x1=-15+5/2=-5
x2=-15-5/2=-10
a(x-x1)(x-x2)
(x+5)(x+10) Это и есть x^2+15x+50