July 2022 1 24 Report
Реакцию между нитратом серебра и хлоридом аммония выражают сокращенным ионным уравнением: 1Ag+ + Сl-= AgCl 22Ag+ + S2- = Ag2S 3NH4+ + ОН- = NH3 + H2O 4H+ + ОН- = H2O
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