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ksyushavlasova1
@ksyushavlasova1
June 2022
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Ребят ,очень надо,помогите,пожалуйста))
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sangers1959
Verified answer
Log(√2) sin(π/8)+log(√2) 2cos(π/8)= log(√2) 2sin(π/8)cos(π/8)=
=log(√2) sin(π/4)=log(√2) √2/2=log(√2) (√2)⁻¹=-1.
log₁/₂(cos(π/6)+sin(π/6))+log₁/₂(cos(π/6-sin(π-6))=log₁/₂ (cos²(π/6)-sin²(π/6))=
=log₁/₂ cos(π/3)=log₁/₂ 1/2=1.
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Answers & Comments
Verified answer
Log(√2) sin(π/8)+log(√2) 2cos(π/8)= log(√2) 2sin(π/8)cos(π/8)==log(√2) sin(π/4)=log(√2) √2/2=log(√2) (√2)⁻¹=-1.
log₁/₂(cos(π/6)+sin(π/6))+log₁/₂(cos(π/6-sin(π-6))=log₁/₂ (cos²(π/6)-sin²(π/6))=
=log₁/₂ cos(π/3)=log₁/₂ 1/2=1.